Vaught's conjecture for superstable theories of finite rank
نویسنده
چکیده
In [Vau61] Vaught conjectured that a countable first order theory has countably many or 2א0 many countable models. Here, the following special case is proved. Theorem. If T is a superstable theory of finite rank with < 2א0 many countable models, then T has countably many countable models. The basic idea is to associate with a theory a ∧ − definable group G (called the structure group) which controls the isomorphism types of countable models of the theory. The theory of modules is used to show that for M |= T , G∩M is, essentially, the direct sum of copies of finitely many finitely generated subgroups. This is the principle ingredient in the proof of the following main theorem, from which Vaught’s conjecture follows immediately. Structure Theorem. Let T be a countable superstable theory of finite rank with < 2א0 many countable models. Then for M a countable model of T there is a finite A ⊂ M and a J ⊂ M such that M is prime over A∪ J , J is A− independent and {st p(a/A) : a ∈ J } is finite. ∗Research supported by NSF. The author wishes to thank Ludomir Newelski and Elisabeth Bouscaren for comments on preliminary versions of the paper.
منابع مشابه
Vaught's conjecture for unidimensional theories
In Bue93b] we proved Vaught's conjecture for all superstable theories of nite rank; that is, such a theory has countably many or continuum many countable models. While this proof does settle Vaught's conjecture for unidimensional theories a sharper result can be obtained for these theories and in places the proof can be simpliied. Let T be a properly unidimensional theory with < 2 @ 0 many coun...
متن کاملVaught's conjecture for superstable theories of nite rank
In this paper we prove Vaught's conjecture for superstable theories in which each complete type has nite U? rank. The general idea is to associate with the theory an V ? deenable group G (called the structure group) which controls the isomorphism types of the models. We use module theory to show that when the theory has few countable models and M is a countable model there is a nice decompositi...
متن کاملOn superstable CSA-groups
We prove that a non-abelian superstable CSA-group has an infinite definable simple subgroup all of whose proper definable subgroups are abelian. This imply in particular that the existence of non-abelian CSAgroup of finite Morley rank is equivalent to the existence of a simple bad group all whose definable proper subgroups are abelian. We give a new proof of a result of E. Mustafin and B. Poiza...
متن کاملThe Vaught Conjecture: Do Uncountable Models Count?
We give a model theoretic proof, replacing admisssible set theory by the LopezEscobar theorem, of Makkai’s theorem: Every counterexample to Vaught’s conjecture has an uncountable model which realizes only countably many Lω1,ω-types. The following two results are new. Theorem I. If a first order theory is a counterexample to the Vaught conjecture then it has 2א1 models of cardinality א1. Theorem...
متن کاملThe Classification of Small Types of Rank Ω , Part I
Certain basic concepts of geometrical stability theory are generalized to a class of closure operators containing algebraic closure. A specific case of a generalized closure operator is developed which is relevant to Vaught’s conjecture. As an application of the methods, we prove Theorem A. Let G be a superstable group of U− rank ω such that the generics of G are locally modular and Th(G) has f...
متن کاملذخیره در منابع من
با ذخیره ی این منبع در منابع من، دسترسی به آن را برای استفاده های بعدی آسان تر کنید
برای دانلود متن کامل این مقاله و بیش از 32 میلیون مقاله دیگر ابتدا ثبت نام کنید
ثبت ناماگر عضو سایت هستید لطفا وارد حساب کاربری خود شوید
ورودعنوان ژورنال:
- Ann. Pure Appl. Logic
دوره 155 شماره
صفحات -
تاریخ انتشار 2008